Friday, September 24, 2010

Quadratic Equations

How to solve quadratic equations:

The additional amount polynomial blueprint is alleged boxlike blueprint in math. The variables are acclimated in boxlike equation. The accepted anatomy of boxlike blueprint is ax2 + bx + c = 0. In this equation, absolute numbers are represented as a, b and c. The chat problems are declared by situation. The chat problems are some difficult to understand. We can break the chat problems by do the boxlike blueprint factorization. Now we are traveling to see about how do you break boxlike blueprint chat problems

Wednesday, September 8, 2010

Formula of percentage

Formula of percentage:

If the value is 0.0235. What is percentage value?

Solution:
= 0.0235
= 0.0235 100%
= 2.35% 



Rectangle defination

Rectangle Defination

A rectangle is a parallelogram with four right angles.

  • Rectangle is one of the classifications of quadrilateral
  • Rectangle consists of four same angles (90°)
  • Rectangle consists of parallel opposite sides and equal length.

Tuesday, September 7, 2010

Algebraic Expressions

Definition of algebraic expressions worksheet

An expression consists of a arrangement of numbers, variables, constants, operators and/or parentheses. Examples include:
3
x
2y − 3
x2 + (4x + 2)/2
25 + (x + 3)3/2z − [5 + z(x+ 1) − 7]

Monday, September 6, 2010

Factors of 21

All the numbers are divisible by 1.
Factors of 21
So , 21 ÷ 1 = 21
Then divide the number by 3.
21 ÷ 3 = 7.
Then the next possible divisor is 7.
21 ÷ 7 = 3.
And then 21 ÷ 21 = 1.
Therefore the factors of 21 are 1 , 3 , 7 , 21.
That is 21 = 1 x 3 x 7.

Friday, September 3, 2010

Diagonal of a Square Problem

Diagonal of a square:

Find the diagonal for a square of side 7.
Solution:
Diagonal is always root 2 times side.
Substituting 7 for side here,
we get diagonal = 7 root 2.
So diagonal of square with side 7 units is 7 root 2 units.

Tuesday, August 31, 2010

Calculus

calculus help free
Write first five terms of the sequence given by the rule an = (2n + 1) and obtain the corresponding series.
Solution:
We have, an = (2n + 1) ...... (1)
Putting n = 1, 2, 3, 4, 5, ..... successively in (1), we get
a1 = (2 * 1 +1) = 3
a2 = (2 * 2 +1) = 5
a3 = (2 * 3 +1) = 7
a4 = (2 * 4 +1) = 9
a5 = (2 * 5 +1) = 11
Hence, the required sequence is 3, 5, 7, 9, 11, ......
The corresponding series is 3 + 5 + 7 + 9 + 11 + .....